Battery wiring to disconnect solenoid
My 2005 24SS came with a single 12 volt, 115 amp hour battery, so I'm modifying the original battery box to add another battery (230 amp hours total) to run an inverter/charger.
The box has the battery disconnect solenoid and a 50 amp circuit breaker mounted on it. These are too small for the amps the inverter/charger will require (100-110 amps peak), so I'm planning to replace them with a 100+ amp manual disconnect switch and a 200 amp fuse (same as in my previous motorhome).
The battery + post has four cables on it - two 4 AWG and two 6 AWG cables. I'm guessing this:
4 AWG: charge lead from Iota converter
4 AWG: charge lead from engine alternator
6 AWG: power lead to 400 watt Xantrex inverter
6 AWG: power lead to the DC distribution box
Question 1: What are these four cables really for? That would save me a bunch of digging around in the wiring.
Question 2: Will replacing the disconnect solenoid and the inline circuit breaker with a manual switch and fuse cause me any problems? I've been surprised by the wiring in this coach before, so I'm trying to avoid more surprises.
Question 3: Can someone post a detailed DC wiring diagram? I have a drawing the factory sent me, but it's a single line style drawing the just hints at how things are connected, and doesn't show those cables I asked about, or other details that would help with installing the new batteries and the inverter/charger.
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