Amp/Volt Question

[dennis b]

Ok guys
answer this!

HOW MANY AMPS = 1 volt

[frieed]

Ohm my God!!

that's similar to "how many gallons per minute = 1 psi"
they are units of measure for different things.

They are related though

1 Volt (think of it as water pressure) will push 1 ampere (GPM) through 1 ohm of resistance (think size of the water pipe).

V/R = I(amps)

[Big Sky]

There are three variables; volts/amps/watts. You'll need two of the variables known in order to answer the third. The answer to your question is that the AMPS will equal the watts of whatever it is you are talking about. Watts = Amps x Volts.

http://www.supercircuits.com/resourc...amps-converter

[wwsmith111]

I have a degree in Electrical Engineering and 35 years experience in the field. I would answer the question but you would think I was showing off.

[Tunce the traveler]

Originally Posted by wwsmith111

I have a degree in Electrical Engineering and 35 years experience in the field. I would answer the question but you would think I was showing off.

So the short answer is if you trip a circuit shut something off!

[Mustang65]

Originally Posted by dennis b

Ok guys
answer this!

HOW MANY AMPS = 1 volt

You need a "LOAD" value (light bulb, electric motor....) to figure out AMPS
Don

[eldermike]

One volt is equal to one Joule of energy per coulomb of charge.

[David472]

Originally Posted by dennis b

Ok guys
answer this!

HOW MANY AMPS = 1 volt

1 amp flowing thru a 1 ohm resistance, will develop a 1 volt drop across that resistance. In doing so, the 1 ohm resistance will dissipate 1 watt of power.

[Seann45]

You need to know watts and amps to get volts..
http://www.supercircuits.com/resourc...amps-converter

Science Concept: Volts, Watts, and Amps


Electricity is measured in terms of amperage, voltage, and wattage. Amperage (amps for short) is a measure of the AMOUNT of electricity used. Voltage (volts) measures the pressure, or FORCE, of electricity. The amps multiplied by the volts gives you the wattage (watts), a measure of the WORK that electricity does per second.
Think of it this way: Electricity flowing through a wire is like water flowing through a garden hose. The amount of water that can fit through the hose depends on the diameter of the hose (amps). The pressure of the water depends on how far open the faucet is (volts). The amount of work that can be done (watts) depends on both the amount and the pressure of the water (volts x amps = watts).

[wwsmith111]

There is more than one correct answer. I see several of you have done some googling. lol But there are still other correct answers...

[David472]

Originally Posted by wwsmith111

There is more than one correct answer. I see several of you have done some googling. lol But there are still other correct answers...

lol you're not the only electrical engineer.

BTW a question for you; what is PIM distortion in a waveguide assembly?

[wwsmith111]

Sorry David472, I design computers. I don't do microwaves or transmission lines. lol

[LkptRvPilot]

So, perhaps I'm reading too hard into this, but it seems to me the question is set up to be a joke or a trick question.

How many amps in a volt? A volt-amps worth? A watts worth? (Wattsworth???)

[wwsmith111]

It is a trick question and a joke LkptRvPilot. lol. But it happens to have an answer, and more than one.

[dennis b]

It started out as a joke, but Looks like there may be a technical answer.

Humm! guess jokes on me lol

[ranchosinvacas]

Yo Dude! Watts up?
Answering the same question regarding volts over two times...
is revolting!!!

[Big Sky]

Originally Posted by wwsmith111

There is more than one correct answer. I see several of you have done some googling. lol But there are still other correct answers...

Well? wow us

[nbhybrid]

Originally Posted by Big Sky

Well? wow us

he can't.....his googles' down

[dennis b]

Watt?

[wwsmith111]

Amps are how many electrons flow past a certain point per second. It is equal to one coulomb of charge per second, or 6.24 x 10^18 electrons per second. Volts is a measure of how much force that each electron is under, which we call "potential". Power (watts) is volts times amps. A few electrons under a lot of potential can supply a lot of power, or a lot of electrons at a low potential can supply the same power. Think of water in a hose. A gallon a minute (think amps) just dribbles out if it is under low pressure (think low voltage). But if you restrict the end of the hose, letting the pressure build up, the water can have more power (like watts), even though it is still only one gallon a minute. In fact the power can grow enormous as the pressure builds, to the point that a water knife can cut a sheet of glass. In the same manner as the voltage is increased a small amount of current can turn into a lot of watts.
This is also why increasing the volts does not necessarily increase the available power. Power is amps times volts, so if you double the volts you halve the amps unless something in your circuit actually creates power, such as a battery, solar panel or nuclear power plant.
One answer which is closest I suppose to the one posed (Amps = Volts) is through the use of Ohm's law: V = IR or I=V/R where I is the current through the conductor in units of amperes, V is the potential difference measured across the conductor in units of volts, and R is the resistance of the conductor in units of ohms. More specifically, Ohm's law states that the R in this relation is constant, independent of the current. This means for example that if R = 1 and V = 1 then I = 1. So, V = I or 1 amp = 1 volt where the resistance = 1 ohm.
Another way to look at it is in some engineering disciplines the volts are more or less fixed in the equation P = VI where P = Power in watts, for example in house wiring, automotive wiring, or telephone wiring. In these fields technicians often have charts that relate amps to watts and this has caused some confusion. What these charts should be titled is "conversion of amps to watts at a fixed voltage of 110 volts" or "conversion of watts to amps at 13.8 volts," etc. Doing the math I = P/V. So we have power as a constant or variable instead of resistance.
There are other ways to look at it using coulombs etc. But the point is if one uses a constant such as household volts i.e. 110v or voltage of an automotive battery 13.6v as is common practice then there is an answer to Amps = Volts albeit extrapolated or based on assumption of constants.
Again, one can simply convert amps to volts at a fixed resistance or wattage.
I hope that is enough as my brain hurts... lol